If it's not what You are looking for type in the equation solver your own equation and let us solve it.
0.1t^2+3t-400=0
a = 0.1; b = 3; c = -400;
Δ = b2-4ac
Δ = 32-4·0.1·(-400)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-13}{2*0.1}=\frac{-16}{0.2} =-80 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+13}{2*0.1}=\frac{10}{0.2} =50 $
| (x+64)+50=180 | | 8=3-9x+4x | | x+5/6=52/3 | | 0=0.1t^2+3t-400 | | -8+5b=-113 | | −2(x9)+25=14−3x | | j-9=7 | | –2b+3=19 | | 0-0.25y=2 | | -9+4t=-37 | | |-r+7|=14 | | v-3.41=7.5 | | 10c+–11c+5c=–20 | | 8x+11=3x+7x+5 | | 126+x+24+7x+34=180 | | w-2+17=14 | | 10x=15+7x | | -5x^2-40x+80=0 | | -5(5x-2)=-2(3+6x) | | 4x+(-3x)=5x+3 | | -5(x+3)+x+3=0 | | 12x+14=9x+17 | | 8m+0=-8 | | 4x-3x=5x+3 | | 5(4x+2)=13=63 | | -6=-5x-71 | | 14+x/4=12 | | 10x-21=9x-7+124 | | -(x+7)=-10 | | 8+0.3x=17 | | 66=4(2x+4) | | –31z=744 |